The Real Reason Dolph Ziggler & Robert Roode Are Teaming In WWE

The thrown-together alliance conquered all on this week's Raw.

Robert Roode Dolph Ziggler
WWE

This week's WWE Raw brought unexpected developments in the tag division as Tag Team Turmoil pitted seven established tandems and a thrown-together Robert Roode/Dolph Ziggler duo against each other for the right to face champions Seth Rollins and Braun Strowman at Clash of Champions.

Surprisingly, Roode and Ziggler won, eliminating The Lucha House Party, The Revival, Curt Hawkins and Zack Ryder, and Heavy Machinery in a dominant closing run. It came out of nowhere, leaving fans asking "why?", and this week's Wrestling Observer Newsletter has the answer.

Dave Meltzer writes that the whole thing was Raw Executive Director Paul Heyman's idea. The former ECW head honcho is apparently a huge fan of Roode and wanted to give him something substantial to do after being booked as a nobody for so long, with him and Ziggler eliminating four other teams designed to make them look strong.

Advertisement

There's currently no word on whether or not Ziggler and Roode will beat Strowman and Rollins or what WWE will do with them after that, but Heyman's support is encouraging for both men. Their pay-per-view victory could be used to build further tension for Strowman and Rollins' Universal Title clash later in the night.

Channel Manager
Channel Manager

Andy has been with WhatCulture for six years and is currently WhatCulture's Senior Wrestling Reporter. A writer, presenter, and editor with 10+ years of experience in online media, he has been a sponge for all wrestling knowledge since playing an old Royal Rumble 1992 VHS to ruin in his childhood. Having previously worked for Bleacher Report, Andy specialises in short and long-form writing, video presenting, voiceover acting, and editing, all characterised by expert wrestling knowledge and commentary. Andy is as much a fan of 1985 Jim Crockett Promotions as he is present-day AEW and WWE - just don't make him choose between the two.